When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + 2c = 3c + 4x + 2 for c in terms of x.
| -3\(\frac{1}{3}\)x + 2\(\frac{2}{3}\) | |
| \(\frac{8}{9}\)x + \(\frac{5}{9}\) | |
| -\(\frac{1}{2}\)x - \(\frac{1}{12}\) | |
| -x - 1 |