ASVAB Math Knowledge Practice Test 582616

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a + 2a = 5a - 5x - 6 for a in terms of x.

-x - 1\(\frac{3}{5}\)
-1\(\frac{2}{5}\)x + \(\frac{2}{5}\)
2\(\frac{1}{3}\)x + 2
-\(\frac{1}{2}\)x - 3\(\frac{1}{2}\)