| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
Solve for a:
-2a + 1 > -8 - 3a
| a > -\(\frac{4}{7}\) | |
| a > -1 | |
| a > \(\frac{1}{3}\) | |
| a > -9 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-2a + 1 > -8 - 3a
-2a > -8 - 3a - 1
-2a + 3a > -8 - 1
a > -9
Solve for x:
x2 + 5x - 6 = 0
| 4 or 2 | |
| 5 or -9 | |
| 1 or -6 | |
| -6 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
x2 + 5x - 6 = 0
(x - 1)(x + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 1) or (x + 6) must equal zero:
If (x - 1) = 0, x must equal 1
If (x + 6) = 0, x must equal -6
So the solution is that x = 1 or -6
Breaking apart a quadratic expression into a pair of binomials is called:
normalizing |
|
deconstructing |
|
squaring |
|
factoring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
If a = c = 6, b = d = 1, and the blue angle = 55°, what is the area of this parallelogram?
| 6 | |
| 36 | |
| 3 | |
| 21 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 6 x 1
a = 6
If the area of this square is 49, what is the length of one of the diagonals?
| 7\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)