ASVAB Math Knowledge Practice Test 586450 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

The dimensions of this cube are height (h) = 6, length (l) = 5, and width (w) = 8. What is the surface area?

51% Answer Correctly
198
62
112
236

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 5 x 8) + (2 x 8 x 6) + (2 x 5 x 6)
sa = (80) + (96) + (60)
sa = 236


2

Simplify (3a)(6ab) + (2a2)(2b).

65% Answer Correctly
36a2b
36ab2
22a2b
14ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(6ab) + (2a2)(2b)
(3 x 6)(a x a x b) + (2 x 2)(a2 x b)
(18)(a1+1 x b) + (4)(a2b)
18a2b + 4a2b
22a2b


3

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

4

3

5

2


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


4

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

4π r2

π r2h2

π r2h

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

Solve 7b + 7b = -8b + 4z + 7 for b in terms of z.

34% Answer Correctly
-\(\frac{1}{5}\)z + \(\frac{7}{15}\)
\(\frac{2}{3}\)z - \(\frac{1}{6}\)
2z - \(\frac{1}{6}\)
\(\frac{1}{2}\)z + \(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

7b + 7z = -8b + 4z + 7
7b = -8b + 4z + 7 - 7z
7b + 8b = 4z + 7 - 7z
15b = -3z + 7
b = \( \frac{-3z + 7}{15} \)
b = \( \frac{-3z}{15} \) + \( \frac{7}{15} \)
b = -\(\frac{1}{5}\)z + \(\frac{7}{15}\)