When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8a + 5a = -4a + 3z + 6 for a in terms of z.
| -\(\frac{1}{3}\)z - 1 | |
| -\(\frac{1}{6}\)z + \(\frac{1}{2}\) | |
| 3\(\frac{3}{4}\)z + 2\(\frac{1}{4}\) | |
| -\(\frac{1}{3}\)z + \(\frac{1}{6}\) |