ASVAB Math Knowledge Practice Test 588412

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5c + 2c = 7c - 6y + 3 for c in terms of y.

4y - 1\(\frac{1}{2}\)
-\(\frac{1}{4}\)y + 1
6y - 7
\(\frac{4}{5}\)y - \(\frac{2}{5}\)