ASVAB Math Knowledge Practice Test 588437

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c + 7c = c - 4z + 7 for c in terms of z.

\(\frac{1}{4}\)z + 1\(\frac{1}{4}\)
-\(\frac{1}{2}\)z + 3\(\frac{1}{2}\)
-5\(\frac{1}{2}\)z + 3\(\frac{1}{2}\)
\(\frac{1}{2}\)z - \(\frac{1}{12}\)