| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
If BD = 22 and AD = 24, AB = ?
| 2 | |
| 4 | |
| 14 | |
| 20 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDSolve for z:
-4z - 6 = -7 - z
| \(\frac{1}{3}\) | |
| 1\(\frac{4}{5}\) | |
| -1\(\frac{1}{3}\) | |
| \(\frac{4}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-4z - 6 = -7 - z
-4z = -7 - z + 6
-4z + z = -7 + 6
-3z = -1
z = \( \frac{-1}{-3} \)
z = \(\frac{1}{3}\)
Which of the following is not true about both rectangles and squares?
all interior angles are right angles |
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the area is length x width |
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the lengths of all sides are equal |
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the perimeter is the sum of the lengths of all four sides |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
If a = -4 and y = -5, what is the value of -9a(a - y)?
| 64 | |
| 350 | |
| 36 | |
| 135 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-9a(a - y)
-9(-4)(-4 + 5)
-9(-4)(1)
(36)(1)
36
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
|
a2 - c2 |
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c2 + a2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)