| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.85 |
| Score | 0% | 57% |
Simplify (y - 4)(y - 2)
| y2 + 6y + 8 | |
| y2 - 6y + 8 | |
| y2 + 2y - 8 | |
| y2 - 2y - 8 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y - 4)(y - 2)
(y x y) + (y x -2) + (-4 x y) + (-4 x -2)
y2 - 2y - 4y + 8
y2 - 6y + 8
If a = 6, b = 1, c = 2, and d = 7, what is the perimeter of this quadrilateral?
| 17 | |
| 23 | |
| 12 | |
| 16 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 6 + 1 + 2 + 7
p = 16
The endpoints of this line segment are at (-2, -1) and (2, 1). What is the slope of this line?
| \(\frac{1}{2}\) | |
| -1\(\frac{1}{2}\) | |
| 1 | |
| 2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -1) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Solve for x:
x2 + x + 4 = -2x + 2
| 1 or -8 | |
| 2 or -4 | |
| 4 or 1 | |
| -1 or -2 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
x2 + x + 4 = -2x + 2
x2 + x + 4 - 2 = -2x
x2 + x + 2x + 2 = 0
x2 + 3x + 2 = 0
Next, factor the quadratic equation:
x2 + 3x + 2 = 0
(x + 1)(x + 2) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 1) or (x + 2) must equal zero:
If (x + 1) = 0, x must equal -1
If (x + 2) = 0, x must equal -2
So the solution is that x = -1 or -2
Find the value of a:
2a + z = -9
5a + 5z = -5
| -8\(\frac{1}{2}\) | |
| \(\frac{5}{9}\) | |
| -8 | |
| -\(\frac{7}{29}\) |
You need to find the value of a so solve the first equation in terms of z:
2a + z = -9
z = -9 - 2a
then substitute the result (-9 - 2a) into the second equation:
5a + 5(-9 - 2a) = -5
5a + (5 x -9) + (5 x -2a) = -5
5a - 45 - 10a = -5
5a - 10a = -5 + 45
-5a = 40
a = \( \frac{40}{-5} \)
a = -8