When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + c = -c + 5z - 8 for c in terms of z.
| -\(\frac{1}{14}\)z - \(\frac{1}{2}\) | |
| \(\frac{1}{3}\)z + 2 | |
| 1\(\frac{1}{3}\)z - 2\(\frac{2}{3}\) | |
| \(\frac{1}{2}\)z + 1 |