ASVAB Math Knowledge Practice Test 59183

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3a - 6a = 3a - z + 1 for a in terms of z.

-1\(\frac{4}{7}\)z - \(\frac{3}{7}\)
z + \(\frac{5}{9}\)
-\(\frac{5}{6}\)z - \(\frac{1}{6}\)
-2\(\frac{1}{5}\)z - 1\(\frac{1}{5}\)