| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.54 |
| Score | 0% | 51% |
Solve for x:
x - 7 < 5 - 3x
| x < -1\(\frac{2}{5}\) | |
| x < -1\(\frac{2}{3}\) | |
| x < 3 | |
| x < -\(\frac{3}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
x - 7 < 5 - 3x
x < 5 - 3x + 7
x + 3x < 5 + 7
4x < 12
x < \( \frac{12}{4} \)
x < 3
For this diagram, the Pythagorean theorem states that b2 = ?
c - a |
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a2 - c2 |
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c2 - a2 |
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c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Solve -9b - 9b = -8b + 3x + 8 for b in terms of x.
| -12x - 8 | |
| 8x + 4 | |
| 3x + 1 | |
| 2\(\frac{2}{5}\)x + \(\frac{1}{5}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-9b - 9x = -8b + 3x + 8
-9b = -8b + 3x + 8 + 9x
-9b + 8b = 3x + 8 + 9x
-b = 12x + 8
b = \( \frac{12x + 8}{-1} \)
b = \( \frac{12x}{-1} \) + \( \frac{8}{-1} \)
b = -12x - 8
Which of the following statements about math operations is incorrect?
you can subtract monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
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all of these statements are correct |
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you can add monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Solve for z:
-3z + 1 = \( \frac{z}{3} \)
| -\(\frac{8}{73}\) | |
| \(\frac{3}{10}\) | |
| \(\frac{10}{11}\) | |
| -6\(\frac{2}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-3z + 1 = \( \frac{z}{3} \)
3 x (-3z + 1) = z
(3 x -3z) + (3 x 1) = z
-9z + 3 = z
-9z + 3 - z = 0
-9z - z = -3
-10z = -3
z = \( \frac{-3}{-10} \)
z = \(\frac{3}{10}\)