| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
If angle a = 21° and angle b = 41° what is the length of angle c?
| 111° | |
| 115° | |
| 87° | |
| 118° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 21° - 41° = 118°
Solve for z:
-5z - 4 > \( \frac{z}{1} \)
| z > -3\(\frac{3}{11}\) | |
| z > \(\frac{7}{31}\) | |
| z > -\(\frac{2}{3}\) | |
| z > -1\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-5z - 4 > \( \frac{z}{1} \)
1 x (-5z - 4) > z
(1 x -5z) + (1 x -4) > z
-5z - 4 > z
-5z - 4 - z > 0
-5z - z > 4
-6z > 4
z > \( \frac{4}{-6} \)
z > -\(\frac{2}{3}\)
If the base of this triangle is 7 and the height is 6, what is the area?
| 66 | |
| 21 | |
| 105 | |
| 42 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 7 x 6 = \( \frac{42}{2} \) = 21
Solve for x:
x2 - 3x - 54 = 0
| -6 or 9 | |
| 6 or 3 | |
| 8 or 3 | |
| 3 or 2 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
x2 - 3x - 54 = 0
(x + 6)(x - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 6) or (x - 9) must equal zero:
If (x + 6) = 0, x must equal -6
If (x - 9) = 0, x must equal 9
So the solution is that x = -6 or 9
A right angle measures:
180° |
|
360° |
|
45° |
|
90° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.