When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 4c = -5c + 6z + 8 for c in terms of z.
| \(\frac{12}{13}\)z + \(\frac{9}{13}\) | |
| 1\(\frac{5}{7}\)z - \(\frac{1}{7}\) | |
| \(\frac{7}{8}\)z + \(\frac{1}{8}\) | |
| 10z + 8 |