| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.80 |
| Score | 0% | 56% |
The dimensions of this cylinder are height (h) = 4 and radius (r) = 7. What is the surface area?
| 126π | |
| 154π | |
| 16π | |
| 208π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(72) + 2π(7 x 4)
sa = 2π(49) + 2π(28)
sa = (2 x 49)π + (2 x 28)π
sa = 98π + 56π
sa = 154π
A quadrilateral is a shape with __________ sides.
4 |
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3 |
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2 |
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5 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
Solve 4b + 9b = -6b - 6z - 9 for b in terms of z.
| -1\(\frac{1}{2}\)z - \(\frac{9}{10}\) | |
| -2\(\frac{1}{4}\)z - 1\(\frac{3}{4}\) | |
| \(\frac{2}{9}\)z - \(\frac{1}{9}\) | |
| z - 2\(\frac{1}{3}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
4b + 9z = -6b - 6z - 9
4b = -6b - 6z - 9 - 9z
4b + 6b = -6z - 9 - 9z
10b = -15z - 9
b = \( \frac{-15z - 9}{10} \)
b = \( \frac{-15z}{10} \) + \( \frac{-9}{10} \)
b = -1\(\frac{1}{2}\)z - \(\frac{9}{10}\)
The endpoints of this line segment are at (-2, -8) and (2, 0). What is the slope of this line?
| -1\(\frac{1}{2}\) | |
| -\(\frac{1}{2}\) | |
| -1 | |
| 2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -8) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (-8.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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vertical, supplementary |
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obtuse, acute |
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acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).