ASVAB Math Knowledge Practice Test 597982

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a - 9a = a + y + 5 for a in terms of y.

2y + 1\(\frac{1}{3}\)
2\(\frac{1}{5}\)y + 1\(\frac{2}{5}\)
10y + 5
-4\(\frac{2}{3}\)y - 1