| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.49 |
| Score | 0% | 50% |
Which of the following statements about math operations is incorrect?
you can multiply monomials that have different variables and different exponents |
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all of these statements are correct |
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you can add monomials that have the same variable and the same exponent |
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you can subtract monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Simplify (9a)(2ab) + (3a2)(6b).
| 2b | |
| 36a2b | |
| 99ab2 | |
| 36ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(9a)(2ab) + (3a2)(6b)
(9 x 2)(a x a x b) + (3 x 6)(a2 x b)
(18)(a1+1 x b) + (18)(a2b)
18a2b + 18a2b
36a2b
On this circle, line segment CD is the:
diameter |
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circumference |
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radius |
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chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The formula for the area of a circle is which of the following?
c = π r2 |
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c = π d2 |
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c = π r |
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c = π d |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Find the value of a:
-5a + z = -5
4a + 2z = 3
| -\(\frac{4}{11}\) | |
| \(\frac{13}{14}\) | |
| 3\(\frac{2}{3}\) | |
| -\(\frac{5}{43}\) |
You need to find the value of a so solve the first equation in terms of z:
-5a + z = -5
z = -5 + 5a
then substitute the result (-5 - -5a) into the second equation:
4a + 2(-5 + 5a) = 3
4a + (2 x -5) + (2 x 5a) = 3
4a - 10 + 10a = 3
4a + 10a = 3 + 10
14a = 13
a = \( \frac{13}{14} \)
a = \(\frac{13}{14}\)