| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
Which of the following expressions contains exactly two terms?
binomial |
|
quadratic |
|
monomial |
|
polynomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Solve for x:
x2 - 2x - 15 = 0
| 6 or -1 | |
| -3 or 5 | |
| -2 or -4 | |
| 5 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
x2 - 2x - 15 = 0
(x + 3)(x - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 3) or (x - 5) must equal zero:
If (x + 3) = 0, x must equal -3
If (x - 5) = 0, x must equal 5
So the solution is that x = -3 or 5
The endpoints of this line segment are at (-2, -6) and (2, 2). What is the slope of this line?
| 2 | |
| -1\(\frac{1}{2}\) | |
| -3 | |
| -1 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, 2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(2.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)If the area of this square is 49, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)
The dimensions of this cube are height (h) = 6, length (l) = 8, and width (w) = 1. What is the volume?
| 576 | |
| 70 | |
| 162 | |
| 48 |
The volume of a cube is height x length x width:
v = h x l x w
v = 6 x 8 x 1
v = 48