ASVAB Math Knowledge Practice Test 603552 Results

Your Results Global Average
Questions 5 5
Correct 0 2.63
Score 0% 53%

Review

1

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

intersects

bisects

trisects

midpoints


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


2

Which of the following statements about a triangle is not true?

58% Answer Correctly

area = ½bh

exterior angle = sum of two adjacent interior angles

sum of interior angles = 180°

perimeter = sum of side lengths


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


3

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 + a2

c - a

a2 - c2

c2 - a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


4

A trapezoid is a quadrilateral with one set of __________ sides.

71% Answer Correctly

parallel

equal length

equal angle

right angle


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


5

Find the value of c:
-c + y = 7
c - 8y = -2

42% Answer Correctly
3
-47
-7\(\frac{5}{7}\)
-3\(\frac{1}{4}\)

Solution

You need to find the value of c so solve the first equation in terms of y:

-c + y = 7
y = 7 + c

then substitute the result (7 - -1c) into the second equation:

c - 8(7 + c) = -2
c + (-8 x 7) + (-8 x c) = -2
c - 56 - 8c = -2
c - 8c = -2 + 56
-7c = 54
c = \( \frac{54}{-7} \)
c = -7\(\frac{5}{7}\)