ASVAB Math Knowledge Practice Test 604290

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2a + 4a = 3a - 5z - 6 for a in terms of z.

-11z - 5
-1\(\frac{1}{3}\)z - \(\frac{5}{12}\)
1\(\frac{4}{5}\)z + 1\(\frac{1}{5}\)
-5z - 2\(\frac{2}{3}\)