| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
A right angle measures:
90° |
|
180° |
|
360° |
|
45° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
If the base of this triangle is 6 and the height is 9, what is the area?
| 91 | |
| 60 | |
| 25 | |
| 27 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 6 x 9 = \( \frac{54}{2} \) = 27
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
2(π r2) + 2π rh |
|
4π r2 |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
This diagram represents two parallel lines with a transversal. If b° = 147, what is the value of d°?
| 150 | |
| 147 | |
| 40 | |
| 160 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with b° = 147, the value of d° is 147.
Solve for a:
a2 - 10 = -4a - 5
| 4 or -9 | |
| 2 or -6 | |
| 1 or -5 | |
| 5 or 2 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 - 10 = -4a - 5
a2 - 10 + 5 = -4a
a2 + + 4a - 5 = 0
a2 + 4a - 5 = 0
Next, factor the quadratic equation:
a2 + 4a - 5 = 0
(a - 1)(a + 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 1) or (a + 5) must equal zero:
If (a - 1) = 0, a must equal 1
If (a + 5) = 0, a must equal -5
So the solution is that a = 1 or -5