When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7c + 3c = 6c - x - 8 for c in terms of x.
| 1\(\frac{1}{2}\)x + \(\frac{1}{6}\) | |
| -4x - 8 | |
| \(\frac{1}{7}\)x + 1\(\frac{1}{7}\) | |
| 1\(\frac{1}{2}\)x + \(\frac{1}{8}\) |