| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
If a = 5, b = 5, c = 8, and d = 5, what is the perimeter of this quadrilateral?
| 21 | |
| 22 | |
| 23 | |
| 16 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 5 + 5 + 8 + 5
p = 23
Simplify (6a)(5ab) + (3a2)(8b).
| 121ab2 | |
| 54a2b | |
| 6ab2 | |
| 54ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(5ab) + (3a2)(8b)
(6 x 5)(a x a x b) + (3 x 8)(a2 x b)
(30)(a1+1 x b) + (24)(a2b)
30a2b + 24a2b
54a2b
Find the value of b:
5b + y = 5
-7b - 8y = -3
| -\(\frac{3}{10}\) | |
| 1\(\frac{4}{33}\) | |
| -1\(\frac{16}{29}\) | |
| 10\(\frac{3}{5}\) |
You need to find the value of b so solve the first equation in terms of y:
5b + y = 5
y = 5 - 5b
then substitute the result (5 - 5b) into the second equation:
-7b - 8(5 - 5b) = -3
-7b + (-8 x 5) + (-8 x -5b) = -3
-7b - 40 + 40b = -3
-7b + 40b = -3 + 40
33b = 37
b = \( \frac{37}{33} \)
b = 1\(\frac{4}{33}\)
If side x = 5cm, side y = 13cm, and side z = 5cm what is the perimeter of this triangle?
| 23cm | |
| 26cm | |
| 33cm | |
| 29cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 5cm + 13cm + 5cm = 23cm
Solve for b:
9b - 1 > 9 - 3b
| b > \(\frac{1}{9}\) | |
| b > \(\frac{5}{6}\) | |
| b > \(\frac{2}{7}\) | |
| b > -2 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
9b - 1 > 9 - 3b
9b > 9 - 3b + 1
9b + 3b > 9 + 1
12b > 10
b > \( \frac{10}{12} \)
b > \(\frac{5}{6}\)