When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 6c = -2c + 3z + 1 for c in terms of z.
| -\(\frac{2}{7}\)z - \(\frac{5}{7}\) | |
| -\(\frac{1}{12}\)z - \(\frac{1}{3}\) | |
| \(\frac{1}{2}\)z - \(\frac{2}{3}\) | |
| -\(\frac{1}{2}\)z + \(\frac{1}{6}\) |