| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
Solve for z:
z2 + 13z + 42 = 0
| 9 or 2 | |
| 1 or -4 | |
| -6 or -7 | |
| 4 or 2 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 + 13z + 42 = 0
(z + 6)(z + 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 6) or (z + 7) must equal zero:
If (z + 6) = 0, z must equal -6
If (z + 7) = 0, z must equal -7
So the solution is that z = -6 or -7
On this circle, line segment CD is the:
chord |
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circumference |
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diameter |
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radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Simplify (6a)(8ab) - (9a2)(8b).
| 120a2b | |
| -24a2b | |
| 120ab2 | |
| 238a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(8ab) - (9a2)(8b)
(6 x 8)(a x a x b) - (9 x 8)(a2 x b)
(48)(a1+1 x b) - (72)(a2b)
48a2b - 72a2b
-24a2b
The dimensions of this trapezoid are a = 6, b = 5, c = 7, d = 2, and h = 5. What is the area?
| 13\(\frac{1}{2}\) | |
| 10\(\frac{1}{2}\) | |
| 37\(\frac{1}{2}\) | |
| 17\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(5 + 2)(5)
a = ½(7)(5)
a = ½(35) = \( \frac{35}{2} \)
a = 17\(\frac{1}{2}\)
The formula for the area of a circle is which of the following?
a = π r |
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a = π d2 |
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a = π d |
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a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.