ASVAB Math Knowledge Practice Test 607482 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

y-intercept

x-intercept

\({\Delta y \over \Delta x}\)

slope


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


2

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
9\( \sqrt{2} \)
8\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


3

Which of the following expressions contains exactly two terms?

81% Answer Correctly

quadratic

binomial

polynomial

monomial


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


4

If a = c = 4, b = d = 3, what is the area of this rectangle?

79% Answer Correctly
8
12
27
3

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 4 x 3
a = 12


5

The dimensions of this cylinder are height (h) = 1 and radius (r) = 7. What is the volume?

62% Answer Correctly
192π
72π
27π
49π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(72 x 1)
v = 49π