ASVAB Math Knowledge Practice Test 608162 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

Simplify (y + 8)(y - 7)

63% Answer Correctly
y2 - 15y + 56
y2 - y - 56
y2 + y - 56
y2 + 15y + 56

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 8)(y - 7)
(y x y) + (y x -7) + (8 x y) + (8 x -7)
y2 - 7y + 8y - 56
y2 + y - 56


2

If b = -3 and y = 1, what is the value of -6b(b - y)?

68% Answer Correctly
84
-72
-210
-144

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-6b(b - y)
-6(-3)(-3 - 1)
-6(-3)(-4)
(18)(-4)
-72


3

The endpoints of this line segment are at (-2, 0) and (2, 6). What is the slope of this line?

46% Answer Correctly
-1\(\frac{1}{2}\)
-2\(\frac{1}{2}\)
1\(\frac{1}{2}\)
3

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, 6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(6.0) - (0.0)}{(2) - (-2)} \) = \( \frac{6}{4} \)
m = 1\(\frac{1}{2}\)


4

Solve for x:
-6x + 8 < -7 + 5x

55% Answer Correctly
x < -4\(\frac{1}{2}\)
x < 1\(\frac{4}{11}\)
x < -3
x < 1\(\frac{4}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-6x + 8 < -7 + 5x
-6x < -7 + 5x - 8
-6x - 5x < -7 - 8
-11x < -15
x < \( \frac{-15}{-11} \)
x < 1\(\frac{4}{11}\)


5

If side a = 8, side b = 4, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{82} \)
\( \sqrt{68} \)
\( \sqrt{65} \)
\( \sqrt{80} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 82 + 42
c2 = 64 + 16
c2 = 80
c = \( \sqrt{80} \)