| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
| Score | 0% | 55% |
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
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midpoints |
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trisects |
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intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Find the value of a:
-7a + x = -8
4a - 3x = -5
| -\(\frac{2}{5}\) | |
| 1\(\frac{12}{17}\) | |
| -1 |
You need to find the value of a so solve the first equation in terms of x:
-7a + x = -8
x = -8 + 7a
then substitute the result (-8 - -7a) into the second equation:
4a - 3(-8 + 7a) = -5
4a + (-3 x -8) + (-3 x 7a) = -5
4a + 24 - 21a = -5
4a - 21a = -5 - 24
-17a = -29
a = \( \frac{-29}{-17} \)
a = 1\(\frac{12}{17}\)
A coordinate grid is composed of which of the following?
all of these |
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y-axis |
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origin |
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x-axis |
The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.
Solve 5a + 6a = a - 2z - 4 for a in terms of z.
| -3\(\frac{1}{3}\)z + 1\(\frac{2}{3}\) | |
| -2z - 1 | |
| \(\frac{7}{10}\)z + \(\frac{1}{10}\) | |
| \(\frac{1}{6}\)z - 1\(\frac{1}{3}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
5a + 6z = a - 2z - 4
5a = a - 2z - 4 - 6z
5a - a = -2z - 4 - 6z
4a = -8z - 4
a = \( \frac{-8z - 4}{4} \)
a = \( \frac{-8z}{4} \) + \( \frac{-4}{4} \)
a = -2z - 1
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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acute, obtuse |
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obtuse, acute |
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vertical, supplementary |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).