ASVAB Math Knowledge Practice Test 608352

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b - 3b = 4b + 4z - 1 for b in terms of z.

2z + 1\(\frac{1}{3}\)
-\(\frac{3}{10}\)z - \(\frac{3}{10}\)
-1\(\frac{1}{5}\)z + \(\frac{2}{5}\)
-1\(\frac{2}{5}\)z + \(\frac{1}{5}\)