ASVAB Math Knowledge Practice Test 609406 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

The endpoints of this line segment are at (-2, -2) and (2, 10). What is the slope of this line?

46% Answer Correctly
1
-1\(\frac{1}{2}\)
3
-\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, 10) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(10.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{12}{4} \)
m = 3


2

Simplify (6a)(6ab) + (3a2)(3b).

65% Answer Correctly
72a2b
27a2b
45a2b
-27a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(6ab) + (3a2)(3b)
(6 x 6)(a x a x b) + (3 x 3)(a2 x b)
(36)(a1+1 x b) + (9)(a2b)
36a2b + 9a2b
45a2b


3

If a = 2, b = 3, c = 4, and d = 3, what is the perimeter of this quadrilateral?

88% Answer Correctly
27
14
21
12

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 2 + 3 + 4 + 3
p = 12


4

Which of the following statements about math operations is incorrect?

71% Answer Correctly

you can add monomials that have the same variable and the same exponent

you can subtract monomials that have the same variable and the same exponent

all of these statements are correct

you can multiply monomials that have different variables and different exponents


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


5

Solve for c:
2c + 8 = \( \frac{c}{-4} \)

46% Answer Correctly
\(\frac{42}{47}\)
1\(\frac{2}{7}\)
-3\(\frac{5}{9}\)
\(\frac{36}{53}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

2c + 8 = \( \frac{c}{-4} \)
-4 x (2c + 8) = c
(-4 x 2c) + (-4 x 8) = c
-8c - 32 = c
-8c - 32 - c = 0
-8c - c = 32
-9c = 32
c = \( \frac{32}{-9} \)
c = -3\(\frac{5}{9}\)