ASVAB Math Knowledge Practice Test 60984 Results

Your Results Global Average
Questions 5 5
Correct 0 2.89
Score 0% 58%

Review

1

What is 5a3 - 3a3?

74% Answer Correctly
2a3
8
2
15a6

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a3 - 3a3 = 2a3


2

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

68% Answer Correctly

h2 x l2 x w2

lw x wh + lh

h x l x w

2lw x 2wh + 2lh


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


3

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and right

equilateral, isosceles and right

isosceles and right

equilateral and isosceles


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


4

On this circle, line segment CD is the:

46% Answer Correctly

chord

circumference

diameter

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for z:
-2z - 7 = \( \frac{z}{-2} \)

46% Answer Correctly
2\(\frac{1}{4}\)
\(\frac{36}{37}\)
\(\frac{10}{13}\)
-4\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-2z - 7 = \( \frac{z}{-2} \)
-2 x (-2z - 7) = z
(-2 x -2z) + (-2 x -7) = z
4z + 14 = z
4z + 14 - z = 0
4z - z = -14
3z = -14
z = \( \frac{-14}{3} \)
z = -4\(\frac{2}{3}\)