| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
What is the area of a circle with a diameter of 4?
| 2π | |
| 4π | |
| 3π | |
| 36π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{4}{2} \)
r = 2
a = πr2
a = π(22)
a = 4π
If side x = 12cm, side y = 11cm, and side z = 8cm what is the perimeter of this triangle?
| 26cm | |
| 25cm | |
| 31cm | |
| 24cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 12cm + 11cm + 8cm = 31cm
Solve for b:
9b + 4 < \( \frac{b}{1} \)
| b < \(\frac{5}{16}\) | |
| b < -\(\frac{45}{53}\) | |
| b < \(\frac{3}{23}\) | |
| b < -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
9b + 4 < \( \frac{b}{1} \)
1 x (9b + 4) < b
(1 x 9b) + (1 x 4) < b
9b + 4 < b
9b + 4 - b < 0
9b - b < -4
8b < -4
b < \( \frac{-4}{8} \)
b < -\(\frac{1}{2}\)
The dimensions of this cylinder are height (h) = 3 and radius (r) = 5. What is the surface area?
| 90π | |
| 40π | |
| 48π | |
| 80π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 3)
sa = 2π(25) + 2π(15)
sa = (2 x 25)π + (2 x 15)π
sa = 50π + 30π
sa = 80π
For this diagram, the Pythagorean theorem states that b2 = ?
c - a |
|
c2 - a2 |
|
c2 + a2 |
|
a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)