ASVAB Math Knowledge Practice Test 613691 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

Solve for c:
-5c - 1 < \( \frac{c}{-3} \)

44% Answer Correctly
c < 1\(\frac{19}{35}\)
c < -\(\frac{3}{14}\)
c < -6
c < -10\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-5c - 1 < \( \frac{c}{-3} \)
-3 x (-5c - 1) < c
(-3 x -5c) + (-3 x -1) < c
15c + 3 < c
15c + 3 - c < 0
15c - c < -3
14c < -3
c < \( \frac{-3}{14} \)
c < -\(\frac{3}{14}\)


2

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

chord

radius

diameter

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

The dimensions of this cube are height (h) = 5, length (l) = 4, and width (w) = 1. What is the volume?

82% Answer Correctly
27
144
288
20

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 5 x 4 x 1
v = 20


4

If side a = 2, side b = 5, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{85} \)
\( \sqrt{29} \)
\( \sqrt{58} \)
\( \sqrt{117} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 52
c2 = 4 + 25
c2 = 29
c = \( \sqrt{29} \)


5

If the base of this triangle is 9 and the height is 1, what is the area?

58% Answer Correctly
4\(\frac{1}{2}\)
45
63
75

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 9 x 1 = \( \frac{9}{2} \) = 4\(\frac{1}{2}\)