When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 5c = 8c - 3x - 2 for c in terms of x.
| 2\(\frac{2}{5}\)x + 1\(\frac{2}{5}\) | |
| -\(\frac{1}{8}\)x + \(\frac{1}{8}\) | |
| 1\(\frac{1}{3}\)x - 2\(\frac{2}{3}\) | |
| -4\(\frac{2}{3}\)x - 2\(\frac{1}{3}\) |