| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
If angle a = 69° and angle b = 39° what is the length of angle c?
| 72° | |
| 117° | |
| 81° | |
| 107° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 69° - 39° = 72°
If the base of this triangle is 8 and the height is 9, what is the area?
| 52 | |
| 36 | |
| 33 | |
| 40 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 8 x 9 = \( \frac{72}{2} \) = 36
Simplify (4a)(9ab) + (8a2)(9b).
| 221ab2 | |
| 36a2b | |
| 221a2b | |
| 108a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(9ab) + (8a2)(9b)
(4 x 9)(a x a x b) + (8 x 9)(a2 x b)
(36)(a1+1 x b) + (72)(a2b)
36a2b + 72a2b
108a2b
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
|
deconstructing |
|
normalizing |
|
factoring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Solve -3b - 8b = -8b + 9y - 3 for b in terms of y.
| -\(\frac{1}{2}\)y + 3 | |
| -y - \(\frac{1}{4}\) | |
| 1\(\frac{7}{10}\)y + \(\frac{1}{2}\) | |
| 3\(\frac{2}{5}\)y - \(\frac{3}{5}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-3b - 8y = -8b + 9y - 3
-3b = -8b + 9y - 3 + 8y
-3b + 8b = 9y - 3 + 8y
5b = 17y - 3
b = \( \frac{17y - 3}{5} \)
b = \( \frac{17y}{5} \) + \( \frac{-3}{5} \)
b = 3\(\frac{2}{5}\)y - \(\frac{3}{5}\)