When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7b + 3b = 2b + 3z - 6 for b in terms of z.
| -\(\frac{2}{3}\)z + 1\(\frac{1}{3}\) | |
| \(\frac{5}{13}\)z - \(\frac{1}{13}\) | |
| z - 1\(\frac{1}{5}\) | |
| -\(\frac{3}{5}\)z + \(\frac{4}{5}\) |