ASVAB Math Knowledge Practice Test 615853

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve b - 4b = -3b - 4y + 6 for b in terms of y.

y - 1
2y - 3
y + 1\(\frac{1}{2}\)
-4\(\frac{1}{4}\)y + 1\(\frac{3}{4}\)