| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.62 |
| Score | 0% | 72% |
A quadrilateral is a shape with __________ sides.
2 |
|
4 |
|
5 |
|
3 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
This diagram represents two parallel lines with a transversal. If d° = 149, what is the value of x°?
| 25 | |
| 23 | |
| 149 | |
| 166 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with d° = 149, the value of x° is 149.
If AD = 11 and BD = 2, AB = ?
| 3 | |
| 2 | |
| 17 | |
| 9 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD
The endpoints of this line segment are at (-2, 7) and (2, 1). What is the slope-intercept equation for this line?
| y = \(\frac{1}{2}\)x + 3 | |
| y = 2x + 1 | |
| y = 3x - 3 | |
| y = -1\(\frac{1}{2}\)x + 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)Plugging these values into the slope-intercept equation:
y = -1\(\frac{1}{2}\)x + 4
What is 8a + 6a?
| 14 | |
| 14a | |
| 2 | |
| a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a + 6a = 14a