When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 4c = -6c + 7z - 2 for c in terms of z.
| 1\(\frac{1}{3}\)z + \(\frac{2}{3}\) | |
| -\(\frac{15}{16}\)z + \(\frac{3}{8}\) | |
| \(\frac{5}{9}\)z + \(\frac{4}{9}\) | |
| \(\frac{1}{3}\)z - \(\frac{2}{9}\) |