When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = 5c - z + 8 for c in terms of z.
| \(\frac{3}{7}\)z + \(\frac{4}{7}\) | |
| -\(\frac{9}{14}\)z - \(\frac{3}{14}\) | |
| 4z - 8 | |
| -4\(\frac{2}{3}\)z + 2\(\frac{1}{3}\) |