To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

2c - 5y = -3c - y - 1
2c = -3c - y - 1 + 5y
2c + 3c = -y - 1 + 5y
5c = 4y - 1
c = \( \frac{4y - 1}{5} \)
c = \( \frac{4y}{5} \) + \( \frac{-1}{5} \)
c = \(\frac{4}{5}\)y - \(\frac{1}{5}\)

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(9a)(8ab) - (9a²)(4b)
(9 x 8)(a x a x b) - (9 x 4)(a² x b)
(72)(a¹⁺¹ x b) - (36)(a²b)
72a²b - 36a²b
36a²b

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

3y + 3 = \( \frac{y}{4} \)
4 x (3y + 3) = y
(4 x 3y) + (4 x 3) = y
12y + 12 = y
12y + 12 - y = 0
12y - y = -12
11y = -12
y = \( \frac{-12}{11} \)
y = -1\(\frac{1}{11}\)

You need to find the value of a so solve the first equation in terms of y:

4a + y = 1
y = 1 - 4a

then substitute the result (1 - 4a) into the second equation:

-2a + 4(1 - 4a) = -5
-2a + (4 x 1) + (4 x -4a) = -5
-2a + 4 - 16a = -5
-2a - 16a = -5 - 4
-18a = -9
a = \( \frac{-9}{-18} \)
a = \(\frac{1}{2}\)

Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).