ASVAB Math Knowledge Practice Test 618948

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3a + 3a = 4a - 2z + 9 for a in terms of z.

1\(\frac{5}{7}\)z + 1\(\frac{2}{7}\)
-1\(\frac{1}{7}\)z + 1\(\frac{2}{7}\)
\(\frac{1}{5}\)z + 1\(\frac{4}{5}\)
5z - 9