When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8a + 4a = 4a - 5y - 3 for a in terms of y.
| \(\frac{15}{16}\)y + \(\frac{7}{16}\) | |
| -2\(\frac{1}{4}\)y - \(\frac{3}{4}\) | |
| -1\(\frac{3}{11}\)y - \(\frac{6}{11}\) | |
| -3\(\frac{1}{4}\)y + 1\(\frac{1}{2}\) |