When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 4c = c - 8z + 8 for c in terms of z.
| -1\(\frac{2}{5}\)z - \(\frac{4}{5}\) | |
| \(\frac{4}{9}\)z - \(\frac{2}{9}\) | |
| \(\frac{1}{8}\)z - 1 | |
| -2\(\frac{2}{5}\)z + 1\(\frac{3}{5}\) |