ASVAB Math Knowledge Practice Test 620061 Results

Your Results Global Average
Questions 5 5
Correct 0 3.02
Score 0% 60%

Review

1

Factor y2 - y - 72

54% Answer Correctly
(y - 9)(y - 8)
(y + 9)(y - 8)
(y + 9)(y + 8)
(y - 9)(y + 8)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -72 as well and sum (Inside, Outside) to equal -1. For this problem, those two numbers are -9 and 8. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - y - 72
y2 + (-9 + 8)y + (-9 x 8)
(y - 9)(y + 8)


2

What is 7a + 2a?

81% Answer Correctly
14a2
9
5a2
9a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a + 2a = 9a


3

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

isosceles and right

equilateral and right

equilateral and isosceles

equilateral, isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


4

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

68% Answer Correctly

2lw x 2wh + 2lh

lw x wh + lh

h x l x w

h2 x l2 x w2


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


5

Find the value of a:
-a + y = -2
-5a + 2y = -3

42% Answer Correctly
-\(\frac{1}{3}\)
-3\(\frac{7}{19}\)
-14
-\(\frac{8}{33}\)

Solution

You need to find the value of a so solve the first equation in terms of y:

-a + y = -2
y = -2 + a

then substitute the result (-2 - -1a) into the second equation:

-5a + 2(-2 + a) = -3
-5a + (2 x -2) + (2 x a) = -3
-5a - 4 + 2a = -3
-5a + 2a = -3 + 4
-3a = 1
a = \( \frac{1}{-3} \)
a = -\(\frac{1}{3}\)