ASVAB Math Knowledge Practice Test 620324

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7c - 8c = 6c - 4z + 2 for c in terms of z.

-5z - 5
4z + 2
\(\frac{3}{5}\)z - \(\frac{3}{5}\)
1\(\frac{1}{4}\)z - 1\(\frac{3}{4}\)