| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.87 |
| Score | 0% | 57% |
This diagram represents two parallel lines with a transversal. If a° = 30, what is the value of x°?
| 167 | |
| 21 | |
| 155 | |
| 150 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with a° = 30, the value of x° is 150.
Which of the following is not required to define the slope-intercept equation for a line?
slope |
|
y-intercept |
|
\({\Delta y \over \Delta x}\) |
|
x-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
If side x = 6cm, side y = 11cm, and side z = 8cm what is the perimeter of this triangle?
| 35cm | |
| 40cm | |
| 26cm | |
| 25cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 6cm + 11cm + 8cm = 25cm
The endpoints of this line segment are at (-2, -2) and (2, -4). What is the slope-intercept equation for this line?
| y = 2x - 4 | |
| y = -2\(\frac{1}{2}\)x - 3 | |
| y = -\(\frac{1}{2}\)x - 3 | |
| y = -\(\frac{1}{2}\)x + 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, -4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)Plugging these values into the slope-intercept equation:
y = -\(\frac{1}{2}\)x - 3
The dimensions of this cylinder are height (h) = 7 and radius (r) = 9. What is the surface area?
| 288π | |
| 100π | |
| 234π | |
| 144π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 7)
sa = 2π(81) + 2π(63)
sa = (2 x 81)π + (2 x 63)π
sa = 162π + 126π
sa = 288π