ASVAB Math Knowledge Practice Test 621447 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

acute, obtuse

supplementary, vertical

obtuse, acute

vertical, supplementary


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


2

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

midpoints

trisects

bisects

intersects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


3

Which of the following expressions contains exactly two terms?

83% Answer Correctly

monomial

polynomial

quadratic

binomial


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


4

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the perimeter is the sum of the lengths of all four sides

the area is length x width

the lengths of all sides are equal

all interior angles are right angles


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


5

Solve for x:
-7x - 4 < -3 + 4x

55% Answer Correctly
x < \(\frac{1}{9}\)
x < \(\frac{1}{2}\)
x < \(\frac{2}{3}\)
x < -\(\frac{1}{11}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-7x - 4 < -3 + 4x
-7x < -3 + 4x + 4
-7x - 4x < -3 + 4
-11x < 1
x < \( \frac{1}{-11} \)
x < -\(\frac{1}{11}\)