The surface area of a cylinder is 2πr² + 2πrh:

sa = 2πr² + 2πrh
sa = 2π(5²) + 2π(5 x 6)
sa = 2π(25) + 2π(30)
sa = (2 x 25)π + (2 x 30)π
sa = 50π + 60π
sa = 110π

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s²

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c² = a² + b²
c² = 2² + 2²
c² = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c² = a² + b²
c² = 9² + 2²
c² = 81 + 4
c² = 85
c = \( \sqrt{85} \)

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-6z - 4 > \( \frac{z}{-4} \)
-4 x (-6z - 4) > z
(-4 x -6z) + (-4 x -4) > z
24z + 16 > z
24z + 16 - z > 0
24z - z > -16
23z > -16
z > \( \frac{-16}{23} \)
z > -\(\frac{16}{23}\)

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a⁷ - 2a⁷ = 1a⁷