ASVAB Math Knowledge Practice Test 623633 Results

Your Results Global Average
Questions 5 5
Correct 0 3.60
Score 0% 72%

Review

1

If angle a = 29° and angle b = 50° what is the length of angle c?

71% Answer Correctly
101°
85°
133°
123°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 29° - 50° = 101°


2

Solve for z:
-9z + 2 > 4 + 6z

55% Answer Correctly
z > -\(\frac{3}{4}\)
z > -\(\frac{2}{15}\)
z > -1
z > -1\(\frac{1}{2}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-9z + 2 > 4 + 6z
-9z > 4 + 6z - 2
-9z - 6z > 4 - 2
-15z > 2
z > \( \frac{2}{-15} \)
z > -\(\frac{2}{15}\)


3

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

3

4

2

5


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


4

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
3\( \sqrt{2} \)
4\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)


5

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

squaring

factoring

normalizing

deconstructing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.